20240313第二次测试-词频统计

Question

可行方案之一

#词频统计

freq = {}  

line = input()

for word in line.split(' '):

    freq[word] = freq.get(word,0)+1

words = sorted(freq.keys())

 

for w in words:

    print ("{word}:{frequence}".format(word=w,frequence=freq[w]))

Answer 1

str1=input('')

strs=sorted(str1.split(' '))

dic={}

strs1=strs

for str in strs:

    if str not in dic.keys():

        dic[str]=1

    else:

        dic[str]+=1

for key,value in dic.items():

    print('{}:{}'.format(key,value))

Comments

第四行删掉

Answer 2

message=input()

list=message.split(' ')

list.sort()

dictionary={}

for l in list:

    if l not in dictionary:

        dictionary[l]=1

    else:

        dictionary[l]=dictionary[l]+1

for k,y in dictionary.items():

    print(k,end=':')

    print(y)