20240313第二测试-排序

Question

#排序

from operator import itemgetter

 

l = []

count = 0

count = int(input())

for i in range(count):

    s = input()

    l.append(tuple(s.split(",")))

 

l = sorted(l, key=itemgetter(0,1,2))

for i in l:

    for item in i:

        print(item, end=' ')

    print()

Answer 1

itemgetter和lambda除了格式稍有不同之外有什么区别吗

Answer 2

n=input()

list=[]

for i in range(0,int(n)):

    list.append(input())

list.sort()

for j in range(0,int(n)):

    str1=list[j]

    str1=str1.split(',')

    for m in range(0,len(str1)):

        if m==0:

            print(str1[m],end=' ')

        elif m<len(str1)-1:

            print(int(str1[m]),end=' ')

        else:

            print(int(str1[m]),end=' \n')